Olena Rybakina played a difficult match in the Indian Wells quarterfinals, defeating Karolina Mukhova in three sets 7-6(4), 2-6, 6-4.

Olena Rybakina eliminated Karolina Mukhova in Indian Wells

The first set was under the control of Mukhova, but in the end it came to a tie-break, where Rybakina won with a score of 7-4 after three lost serves by the player from the Czech Republic.

The second set belonged entirely to Karolina Mukhova, who gained a clear advantage.

In the deciding set, the 2022 Wimbledon winner was more decisive despite missing two match points, managing to win against the world No.76.

The game lasted two hours and 48 minutes.

In the semifinals of the tournament in Indian Wells, Olena Rybakina (10 WTA) will play a match with the winner of world leader Iga Sviatek and Romanian Sorana Kirstya (83 WTA).

Indian Wells will be held from March 6-19 on hard and 96 players have started in the two main draws. The contest offers $8,800,000 each for men and women. Titled champions – Taylor Fritz and Iga Svyatek.